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pav-90 [236]
3 years ago
9

4x + 2 = 2x - 20 what is x​

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
8 0

Step-by-step explanation:

4x + 2 = 2x - 20

4x-2x=-20-2

2x=-22

x=-11

Cloud [144]3 years ago
7 0

Answer:

4 \times  + 2 = 2 \times  - 20

2 \times  + 1 =  \times  - 10

2 \times  -  \times  =  - 10 - 1

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olga_2 [115]
Answer: 3.6 m

Explanation:

28.8 ÷ 8 = 3.6 m
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3 years ago
Please please help me
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3 years ago
20 points<br> What is the value of p in the linear equation ?<br><br> −4<br> −2<br> 2<br> 4
Nikolay [14]

Answer:

p=-2

Step-by-step explanation:

24p+12-18p=10+2p-6  

Subtract what is to the right of the equal sign from both sides of the equation.

24p+12-18p-(10+2p-6)=0

Then pull out the like terms(factors)

Which is: 4p+8

=4(p+2)

Put that to 0 and 4=0 which is not a solution because it's a non-zero constant.

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p=-2

4 0
3 years ago
Read 2 more answers
Please help me solve these are quadratic equations: I​
julia-pushkina [17]

Answer:

\boxed {\boxed {\sf a= 3, b=7, c=2}}

\boxed {\boxed {\sf Y-intercept = c }}

\boxed {\boxed {\sf Minimum}}

Step-by-step explanation:

a. a, b, c

Quadratic equations in standard form are written as:

f(x)= ax^2+bx+c

The exponents are listed from greatest to least. The quadratic is already in this form, so match up the variables and values in the equation.

f(x)= 3x^2+7x+2

a=3 \\b=7 \\c=2

b. Y-intercept

The y-intercept for a quadratic is c.

You can also substitute 0 in for x, because the y-intercept occurs when the quadratic crosses the y-axis (at x=0).

f(0)= 3(0)^2+7(0)+2

f(0)=3(0)+7(0)+2\\f(0)= 0+0+2\\f(0)=2

We know that c=2, so the y-intercept is c.

c. Maximum/minimum

The entire quadratic is positive, so the quadratic opens up and has a minimum.

8 0
3 years ago
Question 2 (5 points)
IrinaK [193]

Answer:

x - y + 5 = 0

Step-by-step explanation:

Given:

  • Line passes through (-2,3) and (2,7)

Required:

  • Find the equation of the line

The equation of the line passing through two points is given by

\frac{y-y_{1} }{y_{2}- y_{1} } =\frac{x_{}- x_{1} }{x_{2} -x_{1} }

So, \frac{y-3}{7-3} =\frac{x-(-2))}{2-(-2)}

\frac{y-3}{4} =\frac{x+2}{2+2}

\frac{y-3}{4} =\frac{x+2}{4}

Now, y-3 = x+2

On rearranging,

x - y + 3 + 2 = 0x - y + 5 = 0

Therefore, the equation of the line is x - y + 5 = 0.

5 0
2 years ago
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