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3 years ago

14

How many significant figures does 2.0 x 10² have?

1 answer:

Masteriza [31]3 years ago

6 0

Answer:

Two sig figs

Explanation:

Non-zero integers always count as sig figs (the 2 before the decimal point), and any trailing zeros at the right end of the number are significant only if there is a decimal point (in this case, the 0 is significant). Therefore, there are 2 sig figs in 2.0 x $10^{2}$

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What are some main points about star formation

AysviL [449]

Explanation:

A Giant Gas Cloud. A star begins life as a large cloud of gas.

A Protostar Is a Baby Star.

The T-Tauri Phase.

Main Sequence Stars.

Expansion into Red Giant.

Fusion of Heavier Elements.

Supernovae and Planetary Nebulae.

6 0

3 years ago

A helium filled weather balloon has a volume of 806 L at 20.9°C and 753 mmHg. it is released and rises to an altitude of 6.8 km,

OLEGan [10]

<h3>Answer:</h3>

1257.45 L

<h3>Explanation:</h3>

We are given;

Initial volume of Helium gas, V1 as 806 L
Initial temperature of Helium gas,T1 as 20.9°C
Initial pressure of Helium gas, P1 as 753 mmHg
Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C

But, K = °C + 273.15

Therefore, T1 = 294.05 K and T2 = 254.05 K

We are required to calculate the new volume of the balloon at 6.8 km.
To determine the new volume we are going to use the combined gas law.
According to the combined gas law, $\frac{P1V1}{T1}=\frac{P2V2}{T2}$

Thus, rearranging the formula;

$V2=\frac{P1V1T2}{P2T1}$

$V2=\frac{(753)(806L)(254.05K)}{(417)(294.05)}$

$V2=1257.45L$

Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L

7 0

3 years ago

How many moles are in 1.204 x 10 to the 24th atoms of carbon

Mrrafil [7]

Two moles because one moles would be 6.02×10 23 atoms 2 moles would equal twice that number of atoms

3 0

3 years ago

What is the formula for phosphorus trihydride

Usimov [2.4K]

PH3
Also known as phosphine

4 0

3 years ago

After two half-lives, how much of the original material has decayed? 25 percent 50 percent 75 percent 100 percent

RideAnS [48]

The original material has decayed 75%

<h3>Further explanation</h3>

Given

two half-life

Required

The decayed sample

Solution

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

t = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

t = 2 x t 1/2

Input the value :

$\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%$

The amount of Nt = 25% No

8 0

3 years ago