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2 years ago

A 11-inch board is cut into 6 equal length pieces. How long is each piece?

Mathematics

1 answer:

Dennis_Churaev [7]2 years ago

4 0

Answer:

1.8inches or 1.83in repeating.

Step-by-step explanation:

divide 11 by 6. you get the decimal 1.83333333. you can either round to 1.8 or do 1.83 with a repeating symbol over the three (small dash above the number).

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Use the substitution method to solve the system of equations. y=4x 8x+y=18

RUDIKE [14]

Answer:

x=3/2, y=6

Step-by-step explanation:

plz mark brainliest!

4 0

3 years ago

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Assume the line of best fit for a data set is given by y=22x+32. What data points are predicted by the line of best fit? Check a

malfutka [58]

Hi. You have to do trial and error with each of the choices to see which of those apply. They are points on the given function y=22x+32 that lie on point (x,y). Just substitute the x-and y values to the function.

a. (10,480) => x = 10, y = 480
y = 480 = 22(10) + 32
480 = 252 (does not apply)

b. (5,142) => x = 5, y = 142
y = 142= 22(5) + 32
142 = 142 (apply)

c. (8,208) => x = 8, y = 208
y = 208 = 22(8) + 32
208 = 208 (apply)

d. (7,154) => x = 7, y = 154
y = 154 = 22(7) + 32
154 = 186 (does not apply)

The answer is B and C.

3 0

2 years ago

Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)

Sedbober [7]

Answer: $\bold{y=-\dfrac{1}{3}x-1}$

<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\$

Next, find the midpoint of (4, 1) and (2, -5):

$Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)$

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

$y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\$

6 0

2 years ago

Aleena expands 2xx+3-5(x-2) as 2x2+3-5x-10. Has she expanded it correctly? Please identify the mistakes and write the correct wa

Nimfa-mama [501]

The given expression is :

2xx+3-5(x-2)

We know that, $x{\cdot}x=x^2$

$=2x^2+3-5(x-2)\\\\=2x^2+3+(-5)(x)+(-5)(-2)\\\\=2x^2+3-5x+10$

Aleena expands 2xx+3-5(x-2) as 2x²+3-5x-10. She is mistaken because the sign before 10 should be +10 instead of -10. Hence, the correct expanded form is 2x²+3-5x+10. Hence, this is the required solution.

5 0

2 years ago

If GF = 3.2 ft, which is a possible measure of TS?

iVinArrow [24]

Answer:

C. 3.2

If GF = 3.2 a possible measure of TS is 3.2

6 0

3 years ago

Read 2 more answers