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2 years ago

How much oxygen does the brain need to stay "conscious"?

Health

2 answers:

Dmitriy789 [7]2 years ago

7 0

Answer: An adults brain requires around 20% of the body's oxygen.

Explanation: Because the brain uses about 25 percent of your oxygen intake, supplying it with enough oxygen is essential. For people with chronic lung diseases, getting enough oxygen is difficult. When the brain doesn't receive the amount of oxygen it needs, cerebral hypoxia can occur.

TEA [102]2 years ago

3 0

Answer:

20% of the body's oxygen supply.

Explanation:

The brain represents just 2% of a person's body weight, yet it uses about 20% of the body's oxygen supply. Without it, the brain can't perform even the most basic functions. The brain relies on glucose to power the neurons that control everything from conscious functions like planning and thought to automatic, unconscious processes like managing heart rate and digestion.

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3 years ago

You are performing a cohort study to look at risk factors for breast cancer in postmenopausal women. If the probability of devel

lapo4ka [179]

Answer:

$E(X) = np = 100 *0.05 = 5$

So we expect about 5 people with the disease in the random sample.

Explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

For this case we can assume that our random variable who represent the number of students that develop the disease is distributed on this way $X \sim Bin(n=100, p =0.05)$

And from definition the expected value is given by:

$E(X) = np = 100 *0.05 = 5$

And the variance is given by:

$Var (X) = np(1-p) = 100*0.05 *(1-0.05) =4.75$

And the deviation is given by:

$Sd(X) = \sqrt{4.75}= 2.179$

So we expect about 5 people with the disease in the random sample.

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3 years ago