The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)
<h3>Further explanation</h3>
13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

Then mol iodine (MW=126.9045 g/mol) :

mol ratio of Cobalt and Iodine in the compound :
Answer:
naoh is called sodium hydroxide,
Explanation:
hope this helps
Answer:
study of chemical used in industries
Answer:
it shows the breakdown of the atom
Explanation:
it will show it molecularly
'cause alphe-particle which was +ve charge, get repulsion from the atom, so he deducted that.......