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3 years ago

what is the proper scientific notation for 0.000476? a.0.476 × 10-3 b.4.76 × 10-4 c.47.6 × 10-5 d.476 × 10-6

Chemistry

1 answer:

-BARSIC- [3]3 years ago

6 0

B. 4.75 × 10-4 is the answer

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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature

Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

$v_0=500$
$\alpha =1.12\times 10^{-4}$
$\Delta \epsilon = 25$

Now,

Increase in volume will be:

⇒ $\Delta V = \alpha\times v_0\times \Delta \epsilon$

By putting the given values, we get

$=1.12\times 10^{-4}\times 500\times 25$

$=1.12\times 10^{-4}\times 12500$

$=1.4 \ mL$

8 0

3 years ago

What is the solution and solvent in Kool-Aid?

alexandr402 [8]

In this solution the solvent is water and the solutes are sugar, artificial flavor and artificial color. Another interesting property of solutions is that different concentrations of solute can be made. As all of you are aware, you can make very sweet Kool Aid and less sweet Kool Aid.

5 0

2 years ago

Read 2 more answers

Name the following compound: CH3-CH2-CH2-CH2-CH3 CH3 CH3

stepan [7]

Answer:

Pentane

Explanation:

since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it $C_{5} H_{12}$

6 0

2 years ago

Please answer number12

densk [106]

Hydrogen maybe but I don’t know for sure

7 0

3 years ago

Calculate the mass of water vapour present in a room of volume 400 m3 that contains air at 27 °C on a day when the relative humi

Alex73 [517]

Answer:

Mass of water = 6251. 706g or 6.25Kg

Explanation:

Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%

Actual vapor pressure, Pw = relative humidity * saturation vapor pressure

Pw = 60% * (35.6 *0.001)atm = 0.0216atm

Note: 1mbar = 0.001atm

Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400

* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles

Note: 1m^3 = 1000dm^3,R is the molar gas constant.

Making n subject of the formula, n = PV/RT

n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles

Mass (g) = number of moles (n) * molar mass

molar mass of water=18g

Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg

6 0

3 years ago