Answer:
A. The pressure will increase 4 times. P₂ = 4 P₁
B. The pressure will decrease to half its value. P₂ = 0.5 P₁
C. The pressure will decrease to half its value. P₂ = 0.5 P₁
Explanation:
Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.
<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>
<em />
<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>
V₂ = 0.25 V₁. According to Boyle's law,
P₁ . V₁ = P₂ . V₂
P₁ . V₁ = P₂ . 0.25 V₁
P₁ = P₂ . 0.25
P₂ = 4 P₁
<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>
T₂ = 0.5 T₁. According to Gay-Lussac's law,
![\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%5Cfrac%7BP_%7B2%7D%7D%7BT_%7B2%7D%7D%5C%5C%5Cfrac%7BP_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%5Cfrac%7BP_%7B2%7D%7D%7B0.5T_%7B1%7D%7D%5C%5C%5C%5CP_%7B2%7D%3D0.5P_%7B1%7D)
<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>
n₂ = 0.5 n₁.
P₁ in terms of the ideal gas equation is:
![P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}](https://tex.z-dn.net/?f=P_%7B1%7D%3D%5Cfrac%7Bn_%7B1%7D.R.T_%7B1%7D%7D%7BV_%7B1%7D%7D)
P₂ in terms of the ideal gas equation is:
![P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cfrac%7Bn_%7B2%7D.R.T_%7B1%7D%7D%7BV_%7B1%7D%7D%3D%5Cfrac%7B0.5n_%7B1%7D.R.T_%7B1%7D%7D%7BV_%7B1%7D%7D%3D0.5P_%7B1%7D)
6 moles to equal that I do t know for sure though
Answer:
The equilibrium constant for the reversible reaction = 0.0164
Explanation:
At equilibrium the rate of forward reaction is equal to the rate of backwards reaction.
The reaction is given as
A ⇌ B
Rate of forward reaction is first order in [A] and the rate of backward reaction is also first order in [B]
The rate of forward reaction = |r₁| = k₁ [A]
The rate of backward reaction = |r₂| = k₂ [B]
(Taking only the magnitudes)
where k₁ and k₂ are the forward and backward rate constants respectively.
k₁ = 0.010 s⁻¹
k₂ = 0.0610 s⁻¹
|r₁| = 0.010 [A]
|r₂| = 0.016 [B]
At equilibrium, the rate of forward and backward reactions are equal
|r₁| = |r₂|
k₁ [A] = k₂ [B] (eqn 1)
Note that equilibrium constant, K, is given as
K = [B]/[A]
So, from eqn 1
k₁ [A] = k₂ [B]
[B]/[A] = (k₁/k₂) = (0.01/0.0610) = 0.0163934426 = 0.0164
K = [B]/[A] = (k₁/k₂) = 0.0164
Hope this Helps!!!
Answer:
c
Explanation:
Gas change and climate change are very similar and thats why its c