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2 years ago

Graph the function. [-X + 1, -10 6. f(x) = x2-9, -3 (2x+1, 3

Mathematics

1 answer:

lapo4ka [179]2 years ago

6 0

Answer:

2x2 - 5x - 12 = 0.

(2x + 3)(x - 4) = 0.

2x + 3 = 0 or x - 4 = 0.

x = -3/2, or x = 4.

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Drake needs to drill holes in a wooden plank. The holes will have a diameter of 0.5 millimeters, with an error allowance of 0.05

Tanzania [10]

Answer:

|x − 0.5| = 0.05

Step-by-step explanation:

Here x represents the diameter,

Since, an error of 0.05 millimeters is allowance in diameter,

Thus, the maximum acceptable diameter = x + 0.05,

And, the minimum acceptable diameter = x - 0.05

According to the question,

The holes will have a diameter of 0.5 millimeters,

Thus, x - 0.05 < 0.5 and 0.5 < x + 0.05

⇒ x - 0.5 < 0.05 and x - 0.5 > - 0.05

⇒ x - 0.5 < 0.05 and -(x -0.5) < 0.05

⇒ |x-0.5| < 0.05

⇒ Option D is correct.

6 0

2 years ago

In the data table shown, if x = 20, then y=

IRISSAK [1]

Answer:

we need the table!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The sum of a number and forty-six

ad-work [718]

$\textsf{Hey there!}$

$\mathsf{\star \ The\ sum\ of\ a\ number\ \&\ forty-six}$

$\frak{Let's\ lable\ the\ keypoints\ so\ it\ can\ be\ easier\ to\ solve}$

$\bullet \ \textsf{The word \bf{\underline{SUM}}}\textsf{\ means\ add/addition}}$

$\bullet\textsf{ \underline{"A number"} is an unknown number so we can lable it as \bf{x}}$

$\bullet\textsf{ \underline{forty-six} is 46}$

$\textsf{The sum (+) does in the middle while \underline{x} \& \underline{46} will either be on left/right}$

$- \ \textsf{We can say that x is on your left}$

$-\ \textsf{ + can be in your middle}$

$- \ \textsf{\& lastly 46 can be on your right}$

$\boxed{\textsf{Thus, your answer SHOULD LOOK like: \boxed{\huge\text{\bf{x + 46}}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

4 0

3 years ago

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

1 year ago

Which expression is equal to 5/9

lesya [120]

Hello, There are endless expressions. Since, you multiply this fraction by a costant k / k

If k = 2

Then,

(5/9) = ( 5/9) × ( k / k)

= (5/9) × ( 2/2)

= (5 × 2 / 9×2)

= 10 / 18
________________

The only restriction for k is zero and the infinite. Because there is no "0/0" and "infinito/ infinito" at math.

3 0

2 years ago