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2 years ago

IM LAZY SO SOMEONE PLZ TELL ME 308 DIVIDED BY 2

Mathematics

2 answers:

Vanyuwa [196]2 years ago

4 0

Answer:

154

Step-by-step explanation:

SVETLANKA909090 [29]2 years ago

4 0

Answer:

154

Step-by-step explanation:

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Write the quadratic equation of the parabola that passes through (-2,5) and has a vertex of (1,-3)

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3 years ago

A tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay

allsm [11]

Answer:

3. $600,000

Step-by-step explanation:

We have been given that a tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay 3% of gross annual sales over $200,000.

Let us find base annual rent.

$\text{Base annual rent}=\$1500\times 12\\\\ \text{Base annual rent}=\$18,000$

Let us find the amount of rent paid as 3% of gross annual sales.

$\$30,000-\$18,000=\$12,000$

Let us find amount of sales over $200,000 by dividing $12000 by 3% or 0.03.

$\frac{\$12,000}{0.03}=\$400,000$

Total sales would be $400,000 plus $200,000.

$\text{Total sales}=\$400,000+\$200,000\\\\ \text{Total sales}=\$600,000$

Therefore, the total sales for that year was $600,000 and 3rd option is the correct choice.

7 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

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3 years ago