3 years ago

Plz help me with this

Mathematics

2 answers:

8090 [49]3 years ago

4 0

Answer:

8.216 put a line on top of the six because it's repeating

Step-by-step explanation:

gtnhenbr [62]3 years ago

3 0

That is your answer

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3 years ago

Whats the vertex at of y-13=2(x+4)^2

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The vertex form:
$y=a(x-h)^2+k$
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What is the arc length of the arc sub tended in a circle with radius 6 and an angle of 7 pi/ 8

KengaRu [80]

Answer:

Formula for the Arc length is given by:

$\text{Arc length} = 2 \pi r \cdot \frac{\theta}{360^{\circ}}$

As per the statement:

radius of circle(r) = 6 units

Angle ( $\theta$ ) = $\frac{7 \pi}{8}$ radian

Use conversion:

$1 rad = \frac{180}{\pi}$

$\frac{7 \pi}{8}$ = $\frac{180}{\pi} \cdot \frac{7 \pi}{8} = \frac{1260}{8} = 157.5^{\circ}$

then;

substitute these given values we have;

Use value of $\pi = 3.14$

$\text{Arc length} = 2\cdot 3.14 \cdot (6) \cdot \frac{157.5^{\circ}}{360^{\circ}}$

$\text{Arc length} = 2\cdot 3.14 \cdot (6) \cdot 0.4375$

Simplify:

$\text{Arc length}=16.485$

Therefore, the arc length of the arc substended in a circle with radius 6 units an angle of 7 pi/8 is 16.485 units

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3 years ago