<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%204x%20%3D%207%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20%5C%5C%20find%2

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3 years ago

0%5C%3A%20x" id="TexFormula1" title=" {x}^{2} - 4x = 7 {x}^{2} + 8x \\ find \: x" alt=" {x}^{2} - 4x = 7 {x}^{2} + 8x \\ find \: x" align="absmiddle" class="latex-formula">
please fast okkkkkk

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

Answer:

${x}^{2} - 4x = 7 {x}^{2} + 8x \\ {x}^{2} - 7 {x}^{2} = 8x + 4x \\ - 6 {x}^{2} = 12x \\ - 6x = 12 \\ x = \frac{12}{ - 6} = - 2 \\ x = - 2 \\ thank \: you$

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Following are the solution to the given choices:

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Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

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$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

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In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$