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Vikentia [17]
3 years ago
13

1. Arock with a mass of 65 kg has a density of 8 kg/cm3. What is the volume?

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer: Volume (V) = 8.125 cubic centimeter

V=\frac{m}{p}

\frac{65}{8}

=  8.125 cubic centimeter

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Is 40% of a class are girls. and 25% of girls play tennis, what is the percent of the class play tennis?
ASHA 777 [7]

Answer: a. 10%

Step-by-step explanation:

Girls in the class = 40%

Girls play tennis = 25%

Percentage of class play tennis = 40%*25% = 0.4*0.25 = 0.1

Percentage of class play tennis = 10%

5 0
3 years ago
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(a^-3bc^0)^-2/(ab^3c^4)^5
mr Goodwill [35]

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List the following elements in proper set notation. Place the elements in numerical order within the set. 0, 1, 123, 4, 34
forsale [732]

Answer:

{0, 1, 4, 34, 123}

Step-by-step explanation:

{0, 1, 4, 34, 123}

8 0
3 years ago
The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16
Sergio [31]

Answer:

We can conclude that the result is significant and production differ in cost variance.

Step-by-step explanation:

Given :

n1 = 16

n2 = 16

s1² = 5.7

s2² = 2.8

α = 0.10

H0 : σ1² = σ2²

H1 : σ1² ≠ σ2²

The test statistic :

Ftest = s1² / s2² =

Ftest = 5.7 / 2.8

Ftest = 2.036

Using the Pvalue from Fratio calculator :

df numerator = 16 - 1 = 15

df denominator = 16 - 1 = 15

Pvalue(2.036, 15, 15) = 0.0898

Pvalue = 0.0898

Since the Pvalue is < α ; We can conclude that the result is significant and production differ in cost variance.

3 0
3 years ago
Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.
Nastasia [14]

Answer:

(a) 4^7

(b) 7^6

(c) \dfrac{1}{16}

(d) 3^{4}

Step-by-step explanation:

We need to simplify the given expressions.

(a)

Consider the given expression is

(4^5)(4^2)

Using the property of exponent, we get

=4^{5+2}            [\because a^ma^n=a^{m+n}]

=4^7

(b)

Consider the given expression is

(7^2)^3

Using the property of exponent, we get

=7^{2\times 3}            [\because (a^m)^n=a^{mn}]

=7^6

(c)

Consider the given expression is

2^{-4}

Using the property of exponent, we get

=\dfrac{1}{2^{4}}            [\because a^{-n}=\dfrac{1}{a^n}]

=\dfrac{1}{16}

(d)

Consider the given expression is

\dfrac{3^8}{3^4}

Using the property of exponent, we get

=3^{8-4}            [\because \dfrac{a^m}{a^n}=a^{m-n}]

=3^{4}

6 0
4 years ago
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