Points A, B, and C are collinear and B lies between A and C. If AC = 48, AB = 2x + 2, and BC = 3x + 6, what is BC?
2 answers:
Answer:
30
Step-by-step explanation:
AC = AB + BC
48 = 2x + 2 + 3x + 6
48 = 5x + 8
48 - 8 = 5x
40 = 5x
40/5 = x
8 = x
Finding BC
BC = 3x + 6
BC = 3(8) + 6
BC = 24 + 6
BC = 30
#2
Coordinate = -3 + 8 = 5
Answer:
BC = 30 5 Step-by-step explanation:
We know that adding AB and BC will give us AC so we can create an equation and solve for x.
2x + 2 + 3x + 6 = 48
~Combine like terms
5x + 8 = 48
~Subtract 8 to both sides
5x = 40
~Divide 5 to both sides
x = 8
Now that we know the value of x, we can solve for BC.
= 3(8) + 6
= 24 + 6
= 30
I would assume 8 is the length of EG so we would add that value to -3 and find where that would be at on the number.
-3 + 8 = 5
Best of Luck!
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2 doesn't work, because that would give you 7/0 on the left.... therefore C and D are out. 4 works, giving .5=.5, so you don't have to test -5 since 4 and -5 is not an option.
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