Answer:
7x^3-7x^2+14x
Step-by-step explanation: hope I helped
Answer:
side c = 150 feet of flowers
Area = 5400 feet squared
concert question:
The converse of the Pythagorean theorem can help you determine whether the roped off area is in the shape of a right triangle because you use the side lengths of each square and enter them into the equation, and if the equation is true, then it is a right triangle
Concession stand question:
The school banner can fit across the length of the concession stand
the following information is missing
The length if the sides: c is 50 feet long, b is 40 foot long, and a is 30-foot long.
The distance between the two red stars of the picture makes the hypotenuse of a right triangle, where two sides of length a (30 ft) are the legs. From Pythagorean theorem, diagonal of square A is:
diagonal² = 30² + 30²
diagonal = √1800 = 42.43 ft
which is longer than the banner.
Blueprint question:
No, diagonal of square C is 70.71ft
2nd blueprint question:
50 square root 2
Gardening group:
50.24 yards
Answer:
see explanation
Step-by-step explanation:
note that 3.28 = 2 × 1.64
This could be a geometric sequence with common ratio r = 2
To obtain the next term multiply the previous term by 2
3.28 × 2 = 6.56
6.56 × 2 = 13.12
1.64, 3.28, 6.56, 13.56 ← first 4 terms in sequence
The answer is about 1.9166
Answer:
A=4000, B=80, C=24
Step-by-step explanation:
You forgot to put the correct area model, I attached it to the answer.
We have the fact that Mountain Q is 4 times the height of Mountain P. That's the "4" we have in the left side of our model. It's like having a multiplication table, next to the "4" we have "A" and upper this we have "1000", the only thing we have to do is multiplify 4*1000=4000. The next letter we have is B and below it we have "320", we divided it by 4, 320/4=80. The last letter we have is C, and is below a "6", we only have to multiplify it by 4, 6*4=24.
At the end we only sum our
- A + 320 + c = 4344 (4 times the height of Mountain P).
- 1000 + B + 6 = 1086(the height of the Mountain P).