4x(-2) + 4 x 7 4x5 + 2x(-1) =[-8 20]
[28 -2 ]
3000 Quick answer
Let your calculator do the work. Be careful how you enter this in. (Are you supposed to estimate it? We'll get around to that.) Write it like this.
1.2 * 10^3 divided by 4 * 10^-1 Your calculator will do this nicely. The trick is the - 1. Put it in the calculator like this.
1.2
*
10
^
3
=
÷
4
*
10
^
(-1)
= The calculator should read 3000
That's one way to do it. Another way is just to do it all by hand. The numbers are easy enough
1.2 * 10^3 means shift the decimal 3 places right. 1 200 which is 1200
4 * 10^-1 can be handled 2 ways 10 to the minus 1 in the denominator becomes 10^1 in the numerator. Notice the sign change on the 10 when you shift if :it becomes plus! That's why you did it.
1200 * 10^1
12000
Now you are still left with 4 in the denominator.
12000/4 = 3000.
The first method always works. The second one gives you a better understanding of how powers work. There are other ways of doing this, but these are the two best, I think.
Answer:
Step-by-step explanation:
Okay so to find the domain and range we need to find the x values and the y values: the domain is x and the range is y. Therefore the start of our x values can be concluded as -5 and the end is 5, so our domain will be -5 < x < 5: Note, I couldn't put the less than or equal to symbol. SO now our range is the values that are up and down, the range does down at 1 and the range is the highest at 3 so we can determine the range is 1 < y < 3. This is a continuous graph, so there is continuous x values and y values in this graph, so it's simple to use the start and the end of the domain and range followed by the possible y and x values which is represented by y and x.
Hope this helps. :)
Answer:
1545.66 rad/h
Step-by-step explanation:
We need to find the angular velocity in rad/hour when wind is moving with a speed of 4.1 rpm.
We know that,
1 revolution = 2π rad
1 hour = 60 minute
So,
So, the required angular velocity is 1545.66 rad/h.
I think the slope =21 m
i am not confirm if its not correct
