What is this!!!!!! what is this

bixtya [17]

Solve for a by simplifying both sides of the equation, then isolating the variable.
a = 1

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]

Kamila [148]

Use the power rule for differentiation:

$\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)$

You can use this formula if you remember that a root is just a rational exponential:

$\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}$

So, remembering that the derivative of the logarithm is 1/x, you have

$\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}$

Which you can rewrite as

$\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}$

3 0

3 years ago

The final scores from the last five games of two basketball teams are given. Jumping Jackrabbits: 70, 65, 72, 80, 73 Leaping Liz

scoundrel [369]

Using the Mean Absolute Deviation(MAD) concept, it is found that:

a) The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

b) The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

<h3>What is the mean absolute deviation of a data-set?</h3>

The mean of a data-set is given by the sum of all observations divided by the number of observations.

The mean absolute deviation(MAD) of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.

The mean absolute deviation represents the average by which the values differ from the mean.

Item a:

For the Jumping Jackrabbits, the mean and MAD are given by:

M = (70 + 65 + 72 + 80 + 73)/5 = 72

MAD = (|70 - 72| + |65 - 72| + |72 - 72| + |80 - 72| + |73 - 72|)/5 = 3.6.

For the Leaping Lizards, the mean and the MAD are given by:

M = (61 + 47 + 70 + 63 + 54)/5 = 59

MAD = (|61 - 59| + |47 - 59| + |70 - 59| + |63 - 59| + |54 - 59|)/5 = 6.8.

The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

Item b:

The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

More can be learned about the Mean Absolute Deviation(MAD) concept at brainly.com/question/3250070

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4 0

2 years ago

Internet access vs. preferred method to communicate with friends

pav-90 [236]

Answer: C)

Step-by-step explanation:

7 0

3 years ago

The figure above shows the probability density function for the random variable x. What is P(3≤x<7)?

qwelly [4]

The value of the probability P(3≤x<7) is 1

<h3>How to evaluate the probability expression?</h3>

The expression is given as: P(3≤x<7)

This is calculated using:

P(3 ≤ x < 7) = P(3) + P(4) + P(5) + P(6)

Using the figure of the probability density function (see attachment), we have:

P(3 ≤ x < 7) = 0.30 + 0.30 + 0.20 + 0.20

Evaluate

P(3 ≤ x < 7) = 1

Hence, the value of the expression is 1

Read more about probability density function at:

brainly.com/question/15318348

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4 0

2 years ago