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nikitadnepr [17]
3 years ago
12

X+21+3x+9 solve for x​

Mathematics
1 answer:
frez [133]3 years ago
7 0

Answer:

This is not an equation. It is an expression, you can't solve for x in an expression

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The line passing through (-2,5) and (2,p) has a gradient of -1/2. <br><br> Fnd the value of p
makkiz [27]

Given:

The line passing through (-2,5) and (2,p) has a gradient of -\dfrac{1}{2}.

To find:

The value of p.

Solution:

If a line passes through two points, then the slope of the line is:

m=\dfrac{y_2-y_1}{x_2-x_1}

The line passing through (-2,5) and (2,p). So, the slope of the line is:

m=\dfrac{p-5}{2-(-2)}

m=\dfrac{p-5}{2+2}

m=\dfrac{p-5}{4}

It is given that the gradient or slope of the line is -\dfrac{1}{2}.

\dfrac{p-5}{4}=-\dfrac{1}{2}

On cross multiplication, we get

2(p-5)=-4(1)

2p-10=-4

2p=-4+10

2p=6

Divide both sides by 2.

p=3

Therefore, the value of p is 3.

4 0
3 years ago
In a class of 40 students 75% wore shorts today how many students wore shorts?​
Stella [2.4K]
The answer is blah blah 30
7 0
2 years ago
Read 2 more answers
In a class, there are 20 girls and 10 boys. What is the percentage of the boys?​
gayaneshka [121]

Answer:

33.33%

Step-by-step explanation:

  • Number of boys=10
  • Number of girls=20
  • Total number of students=

Number of boys + Number of girls

10+20

30

  • Percentage of boys=

10/30×100%

33.33%

4 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
3. Escribe la ecuación de la elipse que cumple con:<br> F1(-3,0) F2(3,0) y a=4
maks197457 [2]

Answer:

90

Step-by-step explanation:

7 0
3 years ago
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