will factor into the following
Set each factor equal to 0:
or
x = +/- 2i x = +/- 6
Answer: 2i, 6, -6
(x-4)² + (x-2)² = x²
(x² - 8x + 16 ) + (x² - 4x + 4) = x
2x² -12x + 20 = x
2x²-12x + 20 - x = 0
2x² - 13x + 20 = 0
(2x-5) (x-4) = 0
2x-5 = 0
2x = 5
x = ⁵/₂
x-4 = 0
x = 4
so x₁ = ⁵/₂ , and x₂ = 4