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muminat
3 years ago
9

FILL IN THE BLANK. HELPPPP!

Chemistry
2 answers:
Sedbober [7]3 years ago
3 0

Answer :The corrected answer is given below;


Weak bases react with <u>water</u> to form the hydroxide ion and the conjugate <u>acid</u> of the base. Concentration in solution does not affect whether an acid or a base is <u>strong </u>or weak.

The strength of an acid or a base is determined by the <u>dissociation constant</u> of the substance in solution.

The acid dissociation constant, <u>Ka</u>, is a quantitative measure of acid strength. A strong acid has a much <u>higher</u> Ka than a weak acid. The Ka of an acid is determined from measured <u>titration</u> values.


Hydrochloric acid and sulfuric acid are <u>completely</u> ionized in solution and are <u>strong</u> acids. Ethanoic acid, which is only about 1 percent ionized, is a <u>weak</u> acid. Magnesium hydroxide and calcium hydroxide are strong <u>base</u>.

adelina 88 [10]3 years ago
3 0

Answer:

water

acid

strong

dissociation constant

Ka

higher

titration

completely

Strong

weak

base

Explanation:

Weak bases react with water to form the hydroxide ion and the conjugate acid of the base. Concentration in solution does not affect whether an acid or a base is strong or weak.

The strength of an acid or a base is determined by the dissociation constant (ka /Kb) of the substance in solution.

The acid dissociation constant, Ka, is a quantitative measure of acid strength. A strong acid has a much higher Ka than a weak acid. The Ka of an acid is determined from measured titration values.

Hydrochloric acid and sulfuric acid are completely ionized in solution and are strong acids. Ethanoic acid, which is only about 1 percent ionized, is a weak acid. Magnesium hydroxide and calcium hydroxide are strong base.

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shusha [124]

Answer:

The volume of ethylene glycol, we must add is 8.2 L

Explanation:

Let's apply the formula for the colligative property of Depression of freezing point, to solve this

ΔT = Kf . m . i

Where ΔT = Fussion T° in pure solvent - Fussion T° in solution

Kf = Cryoscopic constant (equal to 1.86 °C kg/mol for the freezing point of water)

m  = molality (mol of solute in 1kg of solvent)

i = The number of ions dissolved in solution. As it is a non-electrolytic compound, the i values 1 (Van't Hoff factor)

0°C - (-25°C) = 1.86 kg°C/mol . m

25°C / 1.86 m/kg°C = m

13.4 = mol/kg

As water density is 1 g/ml, let's convert firstly 11L in mL

11L .1000 = 11000mL

In conclusion, we have 11000 g of water.

density = mass / volume

So, if we have 13.4 moles in 1 kg of water, how many moles of ethylene glycol do we have, in 11000 g of water.

11000 g = 11kg

1 kg _____ 13.4 moles of ethylene glycol

11 kg _____ (11 . 13.4)/1 = 147.4 moles

Molar mass of ethylene glycol = 62.07 g/m

Moles . molar mass = mass

147.4 m  . 62.07g/m = 9149.1 g

Now we can apply density of ethylene glycol to find out the volume

Density ethylene glycol = ethylene glycol mass / ethylene glycol volume

1.11 g/ml = 9149.1 g / ethylene glycol volume

ethylene glycol volume = 9149.1 g/ 1.11 g/ml

ethylene glycol volume = 8242 mL

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8 0
4 years ago
To what temperature must a balloon, initially at 25°C and 2.00 L, be heated in order to have a volume of 6.00 L
andreyandreev [35.5K]

Answer:

894 deg K

Explanation:

The computation is shown below:

Given that

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T1 denotes the initial temperature of gas = 25 + 273 = 298 K  

V2 denotes the final volume of gas  = 6.00 L  

T2 = ?

Based on the above information

Here we assume that the pressure is remain constant,

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V1 ÷ T1 = V2 ÷ T2  

T2 = T1 × V2 ÷ V1

= (298)(6) ÷ (2)

= 894 deg K

6 0
3 years ago
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astraxan [27]
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3 years ago
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Answer:

See below

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E.g., an sample of the same substance had an absorbance of 0.35.  Find that on the x scale and then determine the concentration that would be required to produce that level of absorbance.  0.483M in this case.

8 0
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What is hypothesis please help
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5 0
3 years ago
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