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tangare [24]
3 years ago
14

The following reaction is exothermic. C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g)C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) Predict the effect (shi

ft right, shift left, or no effect) of increasing and decreasing the reaction temperature.
Chemistry
2 answers:
inna [77]3 years ago
7 0

Answer:

Increasing temperature = balance will shift to the left

Decreasing temperature = balance will shift to the right

Explanation:

Step 1: Data given

The increase or decrease in temperature can have an influence on the position of the equilibrium.

If the temperature is increased, the system will ensure that less heat is released. So the balance will shift to the left.

When the temperature drops, however, the system will produce more heat: the balance will shift to the right.

Step 2: The balanced equation

C6H12O6(s) + 6O2(g) ⇌ 6CO2(g) + 6H2O(g)

This is an endothermic reaction

Step 3: Increasing the temperature

If the temperature were increased, the heat content of the system would increase.

In exothermic reactions, increase in temperature decreases the K value. This means less products will be formed. The balance will shift to the left.

Step 4: Decreasing the temperature

If the temperature were decreased, the heat content of the system would increase.

In exothermic reactions, decrease in temperature increases the K value. This means more products will be formed, less reactants. The balance will shift to the right.

elena55 [62]3 years ago
4 0

Answer:

According to Le Chatelier's principle, increasing the reaction temperature of an exothermic reaction causes a shift to the left and decreasing the reaction temperature causes a shift to the right.

Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

1. for an exothermic reaction, on increasing the temperature, there is a shift in equilibrium to the left and formation of the product is favoured.

2. if the temperature of the system is decreased, the equilibrium shifts to right and the formation of the reactants is favoured.

3. if the reaction temperature is kept constant, the system is at equilibrium and there is no shift to the right nor to the left.

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Which word refers to the spatial arrangement of interacting molecules?
PtichkaEL [24]

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2 years ago
Complete the following equation: 250/96Cm ——-> ? + 4 1/0n
vfiekz [6]

Answer:

²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n

Explanation:

The complete equation is;

²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n

  • The above equation is an example of a nuclear reaction in which unstable atom of Cm emits neutrons to become more stable.
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3 0
3 years ago
Enter your answer in the provided box. The usefulness of radiocarbon dating is limited to objects no older than 50,000 yr. What
guapka [62]

Answer : The percent of the carbon−14 left is, 0.242 %

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

To calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5.73\times 10^3\text{ years}}

k=1.205\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount left.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = 1.205\times 10^{-4}\text{ years}^{-1}

t = time taken for decay process  = 50000 years

a = initial amount or moles of the reactant  = 7 g

a - x = amount or moles left after decay process  = ?

Putting values in above equation, we get:

1.205\times 10^{-4}=\frac{2.303}{50000\text{ years}}\log\frac{7g}{a-x}

a-x=0.0169g

The amount left of carbon-14 = 0.0169 g

Now we have to calculate the percent of the carbon−14 left.

\text{Percent of carbon}-14\text{ left}=\frac{\text{Amount left of carbon}-14}{\text{Original amount of carbon}-14}\times 100

\text{Percent of carbon}-14\text{ left}=\frac{0.0169g}{7g}\times 100=0.242\%

Therefore, the percent of the carbon−14 left is, 0.242 %

8 0
3 years ago
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