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Sladkaya [172]
3 years ago
9

To what temperature must a balloon, initially at 25°C and 2.00 L, be heated in order to have a volume of 6.00 L

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

894 deg K

Explanation:

The computation is shown below:

Given that

V1 denotes the initial volume of gas = 2.00 L  

T1 denotes the initial temperature of gas = 25 + 273 = 298 K  

V2 denotes the final volume of gas  = 6.00 L  

T2 = ?

Based on the above information

Here we assume that the pressure is remain constant,

So,  

V1 ÷ T1 = V2 ÷ T2  

T2 = T1 × V2 ÷ V1

= (298)(6) ÷ (2)

= 894 deg K

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Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

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Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

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0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.

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It means that at temperatures higher than 660 K the reaction will be spontaneous.

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