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daser333 [38]
3 years ago
6

Solve for x: 3 < x + 3 < 6

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

x:3-3<x+3-3<6-3

0<x<3

do you get the process?

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Suppose KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. Prove that A is equidistant from LM and KN.
Neporo4naja [7]

Answer:

This is proved by ASA congruent rule.

 Step-by-step explanation:

Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ

we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.

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∠PNA=∠ALQ    (∵alternate angles)  

AN=AL   (∵diagonals of parallelogram bisect each other)

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Hence, by CPCT  i.e Corresponding parts of congruent triangles PA=AQ

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7 0
3 years ago
Please show your work; only #8!
lorasvet [3.4K]

Answer:

x = 0.16

Step-by-step explanation:

Step 3:

Solve the equation for  x  by finding  a ,  b , and  c  of the quadratic then applying the quadratic formula.

x = - \frac{11 - \sqrt{185} }{16}

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8. y=2x+6

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Use point slope form to figure out the y intercept. Because it needs to be parallel, the same slope will be used to solve for point slope form.

8 0
3 years ago
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