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daser333 [38]
2 years ago
6

Solve for x: 3 < x + 3 < 6

Mathematics
1 answer:
timurjin [86]2 years ago
7 0

Answer:

x:3-3<x+3-3<6-3

0<x<3

do you get the process?

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Answer:

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2 years ago
ANSWER ASAP!! WILL MARK BRAINLIEST!! Consider the following algebraic statements and determine the values of x for which each st
Levart [38]

Answer:

x>=0

Step-by-step explanation:

From the equation, we can see that x must be greater or equal to 0. This is true because every answer to an absolute value is positive or equal to 0. That is your answer.

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3 years ago
Plz help me. I forgot how to do this XD
nirvana33 [79]
This question has to do with making an approximation based on the diagram of the angle. Angle KLM is an obtuse angle meaning it is larger then 90° but is also less than 180°. The only choices that lie within this range are choices B and D. However, it is safe to assume that angle KLM is closer to 180° than to 90° based on the diagram, therefore the answer must be choice B.

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3 years ago
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

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2 years ago
Mr. Daniel has 1 2/3 acres of land in which he plans to fertilize. If each bag of fertilizer covers 1/9 of an acre and be bought
tensa zangetsu [6.8K]
He will have 5 bags leftover.
7 0
2 years ago
Read 2 more answers
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