There are one, tens and seven, ones in seventeen
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A) 5 to be chosen among a Total : 10 Men + 8 Women
¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five
b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56
So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees
c) 3 Women and 2 Men:
⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M
d) More women than men, it means:
3 W + 2 M OR (we have found it in c) = 2,520)
4 W + 1 M OR ⁸C₄ x ¹⁰C₁ →→→→ = 700
5 W + 0 M OR ⁸C₅ x ¹⁰C₀ →→→→ = 56
Total where W>M = 3,276 groups of 5 where women are at least 3
Answer:
order is
αb<αc<αa
Step-by-step explanation:
in a )
number 4 and number 12 are showing 3 bullets while number 7 and 9 showing 2 bullets hence
standard deviation for a=3-2=1
in b)
number 4 ,7,9 and number 12 are showing 2 bullets while number 3 and 13 showing 1 bullet hence
standard deviation for a=2-1=1
in c)
number 4 ,7,9 and number 12 are showing 2 bullets while number 5 and 11 showing 1 bullet hence
standard deviation for a=2-1=1
order isαb<αc<αa
