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Minchanka [31]
3 years ago
9

What is a situation in which you might locate points on a coordinate grid?

Mathematics
1 answer:
Ugo [173]3 years ago
8 0
Imagine you are a company owner, you make hats. And each of your employees make different amounts of hats, so you can plot in a grid, the employee (give her a number) and the amount of hats she makes. Then you can plot the employee number in the x axis and the amount of hats she makes in the y axis, so yo can locate in a coordinate grid, how much each employee does.
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The path of a roller coaster over a particular length of track can be represented by a quadratic function f, where f(x) represen
alexgriva [62]
The roller coaster could be represented by the function for Choice D.

If you were to graph this function, you would find that the zeros (x-intercepts) of the function are at the points of -2 and 1. Those are the needed points in the problem.

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STALIN [3.7K]
Company A pays $5500 more than B in year 10

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Jessie has a piece of wood that is 8 feet long. He needs to cut pieces that are 7/8 of a foot long. How many pieces will he be a
balandron [24]
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3 0
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Volgvan

Answer:

it might be D

Step-by-step explanation:

im pretty sure

4 0
3 years ago
The simplified expression
Romashka-Z-Leto [24]

Answer:

5x^2 y^2

Step-by-step explanation:

We need to use the properties shown below to solve this:

1. \sqrt[n]{x^a} =x^{\frac{a}{n}}

2. \sqrt{x}\sqrt{x}  =x

3.  \sqrt{x} \sqrt{y}=\sqrt{x*y}

Area of a triangle is given by  1/2 * base * height, so we do that and simplify:

A=\frac{1}{2}(\sqrt{5x^3} )(2\sqrt{5xy^4} )\\A=\frac{1}{2}(5x^3)^{\frac{1}{2}}*2*(5xy^4)^{\frac{1}{2}}\\A=\sqrt{5}x^{\frac{3}{2}}*\sqrt{5}\sqrt{x} }  y^2\\A=\sqrt{5} \sqrt{5}x^{\frac{3}{2}} x^{\frac{1}{2}}y^2\\A=5*x^2y^2\\A=5x^2 y^2

6 0
3 years ago
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