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Sveta_85 [38]
2 years ago
10

PLEASE HELPPPP ILL MARK BRAINLIEST

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
7 0
Coordinate 1 is : (0,3)
Coordinate 2 is : (-4,-2)
Coordinate 3 is : (-1,-5)
Coordinate 4 is (4,0)
Hope this helps!
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Find m∠USW if m∠USW = 7x - 34 and m∠TSR = 4x + 9.
nikitadnepr [17]

In this question, it is given that the measurement of angles USW and TSR are 7x-34 and 4x+9 .

First we have to find the relationship between those two angles .

And these angles are vertical opposite angles which are congruent .

Therefore

m \angle USW = m \angle TSR

7x-34 = 4x+9
\\
3x = 43
\\
x = 14.33

Therefore measurement of angle USW is

=7(14.33)-34 =66.31 degree

5 0
2 years ago
Find the derivative of f(x) = 6/x at x = -2. select one: a. 6 b. 3/2 c. -3/2 d. -6
Ivenika [448]
F(X) = 6/X

F(X) = 6 • 1/X

F(X) = 6 • x^-1

F(X) = 6x^-1

F'(X) = 6 • d(x^-1)/dx

F'(X) = 6 • -1x^-1-1

F'(X) = 6 • -1x^-2

F'(X) = -6x^-2

F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2

The solution would be C. -3/2.
5 0
2 years ago
(4a - 6) (30-26 +5)​
Yuki888 [10]

Answer:

36a-54

Step-by-step explanation:

(4a - 6) (30-26 +5)

(4a - 6) (9)

36a-54

plz mark as brainliest if it helps

4 0
3 years ago
What does -5+3x equals
SCORPION-xisa [38]

Answer:

10

Step-by-step explanation:

10-10=0

7 0
3 years ago
Read 2 more answers
25-42 Differentiate the function.<br> 25. <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2B5%5E%7Bx%7D" id="TexFormula
natulia [17]

Answer:

<u>y'= 5x^4 + 5^x In(5)</u>

Step-by-step explanation:

<u>Differentiate</u><u> </u><u>with </u><u>Respect</u><u> </u><u>to</u><u> </u><u>x</u>

<u>f(</u><u>x)</u><u>'</u><u>=</u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>In(</u><u>5</u><u>^</u><u>x</u><u>)</u>

<u>f(</u><u>x)</u><u>'</u><u>=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>x </u><u>In(</u><u>5</u><u>)</u>

<u>with </u><u>respect</u><u> </u><u>to </u><u>x,</u><u> </u><u>we </u><u>have</u>

<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>y </u><u>In(</u><u>5</u><u>)</u>

<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>5</u><u>^</u><u>x</u><u> </u><u>In(</u><u>5</u><u>)</u>

8 0
2 years ago
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