In this question, it is given that the measurement of angles USW and TSR are 7x-34 and 4x+9 .
First we have to find the relationship between those two angles .
And these angles are vertical opposite angles which are congruent .
Therefore


Therefore measurement of angle USW is

F(X) = 6/X
F(X) = 6 • 1/X
F(X) = 6 • x^-1
F(X) = 6x^-1
F'(X) = 6 • d(x^-1)/dx
F'(X) = 6 • -1x^-1-1
F'(X) = 6 • -1x^-2
F'(X) = -6x^-2
F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2
The solution would be C. -3/2.
Answer:
36a-54
Step-by-step explanation:
(4a - 6) (30-26 +5)
(4a - 6) (9)
36a-54
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Answer:
10
Step-by-step explanation:
10-10=0
Answer:
<u>y'= 5x^4 + 5^x In(5)</u>
Step-by-step explanation:
<u>Differentiate</u><u> </u><u>with </u><u>Respect</u><u> </u><u>to</u><u> </u><u>x</u>
<u>f(</u><u>x)</u><u>'</u><u>=</u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>In(</u><u>5</u><u>^</u><u>x</u><u>)</u>
<u>f(</u><u>x)</u><u>'</u><u>=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>x </u><u>In(</u><u>5</u><u>)</u>
<u>with </u><u>respect</u><u> </u><u>to </u><u>x,</u><u> </u><u>we </u><u>have</u>
<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>y </u><u>In(</u><u>5</u><u>)</u>
<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>5</u><u>^</u><u>x</u><u> </u><u>In(</u><u>5</u><u>)</u>