Let's say the side length of square A is x, which means the side length of square B is 2x.
Then, the area of square A can be written as , and the area of square B can be written as .
There's no diagram here with shaded region, so I'll just find the area of square A as a percentage of the area of square B:
= 1/4 = 25%
So, the answer is 25% (note this is the answer to the question: "express the area of square A as a percentage of the area of square B; there is no diagram showing me where the shaded area is, so I cannot answer the original question
Answer:
35/36
Step-by-step explanation:
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The slope of the line is “rise over run.” That’s the vertical change between the two points (the difference in the y-coordinates) divided by the horizontal change over the same segment (the difference in the x-coordinates).
Answer:
x = 7
Step-by-step explanation:
if ABC ~ DEF than AB ~ ED, AC ~ DF, and CB ~ FE
The ratio of AB to ED is given as 5/30 = 1/6
For AC ~ ED the ratio would be same x/42 = 1/6 cross multiply it
6x = 42
x = 7
Answer:
- 0.83
- 0.9
- steeper than
- slower than
Step-by-step explanation:
Letting t=1 in Ted's equation, we find that he climbs 5/6 stairs in 1 second. As a decimal, 5/6 ≈ 0.83.
Michael climbs 9 stairs in 10 seconds so his rate is ...
... (9 stairs)/(10 seconds) = (9/10) stairs/second = 0.9 stairs/second
Michael's graph will be a line with a slope of 0.9; Ted's graph will be a line with a slope of about 0.83, so the line on Michael's graph is steeper.
Ted climbs fewer stairs per second, so his rate is slower than Michael's.
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<em>Comment on the problem</em>
You're being asked to compare two different rates that are associated with two different people. First the comparison is one way, then it is the other way. This can be confusing. It might be helpful to draw and label a simple chart to help you keep it straight. (The attachment is such a chart scribbled on a bit of scratch paper. It is sufficient for the purpose.)