Answer:
1. ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y)
2. ∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
Step-by-step explanation:
If we negate a quantified statement, first we negate all the quantifiers in the statement from left to right, ( keeping the same order ) then we negative the statement,
Here, the given statement,
1. ∃y ∈Z such that ∀x ∈Z, R (x + y)
By the above definition,
Negation of this statement is ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y),
2. Similarly,
The negation of statement ∀x ∈Z, ∃y∈Z such that R(x + y),
∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
The value is 1, any number multiplied by 0 is 1
Answer:
P-value = 0.0368
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 101.5
Sample mean,
= 106.4
Sample size, n = 30
Alpha, α = 0.05
Population standard deviation, σ = 15
First, we design the null and the alternate hypothesis
We use One-tailed(right) z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We reject the null hypothesis and accept the alternate hypothesis. Thus, students in Pennsylvania have an IQ that is significantly greater than the state average.
P-value can be calculated with the standard normal table.
P-value = 0.0368
P-value is lower than the significance level.