The answer is 11 1/2 as a mixed number
Answer:
225
Step-by-step explanation:
A = 5. 3A = 3(5) cubed. So 3 times 5 is 15. 15 cubed is 225.
6 is c, i'm not entirely sure about 7
Answer:
Original rectangle: Since the area of a rectangle is the length * width, the area of this rectangle is 7 * 2 = 14 square cm.
New rectangle: The new dimensions of this are 7*3 = 21 cm by 2*3 = 6 cm. To find the area, we multiply these two together. 21*6 = 126 square cm.
126 is 9 times greater than 14, so the area will be multiplied by 9.
Step-by-step explanation:
Throughout all of these steps I'm only going to alter the left hand side (LHS). I am NOT going to change the right hand side (RHS) at all.
Before I change the LHS of the original equation, let's focus on the given identity
cot^2(x) + 1 = csc^2(x)
Since we know it's an identity, we can subtract 1 from both sides and the identity would still hold true
cot^2(x) + 1 = csc^2(x)
cot^2(x) + 1-1 = csc^2(x)-1
cot^2(x) + 0 = csc^2(x)-1
cot^2(x) = csc^2(x)-1
So we'll use the identity cot^2(x) = csc^2(x)-1
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Now onto the main equation given
cot^2(x) + csc^2(x) = 2csc^2(x) - 1
cot^2(x) + csc^2(x) = 2csc^2(x) - 1 .... note the term in bold
csc^2(x)-1 + csc^2(x) = 2csc^2(x) - 1 .... note the terms in bold
[ csc^2(x) + csc^2(x) ] - 1 = 2csc^2(x) - 1
[ 2csc^2(x) ] - 1 = 2csc^2(x) - 1
2csc^2(x) - 1 = 2csc^2(x) - 1
The bold terms indicate how the replacements occur.
So the original equation has been proven to be an identity because the LHS has been altered to transform into the RHS
