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ser-zykov [4K]
3 years ago
13

CAN SOMEONE ELPAIN TGIS THING IN NUBERS PLS PSLS PLSS!SONDHUDUBEUB

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
Eight hundred thousand
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AHHH HELP ILL GIVE BRAINLIEST!!!
just olya [345]

Answer:

B

Step-by-step explanation:

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2 years ago
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When using bits to represent fractions of a number, can you create all possible fractions?.
mafiozo [28]

Every rational number has a base-2 representation, but only the ones with denominators that are powers of 2 will require a finite number of bits to fully represent it.

For example,

\dfrac12 = 1\cdot2^{-1} = 0.1_2

\dfrac14 = 1\cdot2^{-2} = 0.01_2

\dfrac34 = \dfrac12 + \dfrac14 = 0.11_2

\dfrac{1023}{1024} = 1 - \dfrac1{2^{10}} = 1_2 - 0.0000000001_2 = 0.1111111111_2

whereas a number whose denominator contains anything else like 1/3 will need an infinite number of bits to represent it exactly.

\dfrac13 = \dfrac1{2^2} + \dfrac1{12} = \dfrac1{2^2} + \dfrac1{2^4} + \dfrac1{48} = \dfrac1{2^2} + \dfrac1{2^4} + \dfrac1{2^8} + \dfrac1{192}

and so on, so that it has a repeating but non-terminating base-2 representation

\dfrac13 = 0.010101\ldots_2

5 0
1 year ago
Find the measure of angle C of a triangle ABC, if angle A=a and angle B= 2a.
erma4kov [3.2K]
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Because
180o = 3.14 radian
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2 years ago
beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle
Wittaler [7]

Answer:

Step-by-step segment dc bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if segment dc bisects segment ab, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if segment ad bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from:

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Can you help me do this please
Salsk061 [2.6K]
The top part equals 1 because anything to the power of zero equals one. then for the second one bring every variable with a negative exponent to the top and leave the 2 at the bottom
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2 years ago
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