
___________

____________

____________
![\large\begin{array}{l}\\\\ \textsf{Therefore,}\\\\ \mathsf{\#\big[S\cap (A\cup B)\big]}\\\\ =\mathsf{\#\big[(S\cap A)\cup(S\cap B)\big]}\\\\ =\mathsf{\#(S\cap A)+\#(S\cap B)-\#\big[(S\cap A)\cap(S\cap B)\big]}\\\\ =\mathsf{350+100-50}\\\\ =\mathsf{450-50}\\\\ =\mathsf{400~elements.}\\\\\\ \textsf{There are 400 integers in S that are divisible by 2 or 7.} \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%5C%5C%5C%5C%20%5Ctextsf%7BTherefore%2C%7D%5C%5C%5C%5C%20%5Cmathsf%7B%5C%23%5Cbig%5BS%5Ccap%20%28A%5Ccup%20B%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5C%23%5Cbig%5B%28S%5Ccap%20A%29%5Ccup%28S%5Ccap%20B%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5C%23%28S%5Ccap%20A%29%2B%5C%23%28S%5Ccap%20B%29-%5C%23%5Cbig%5B%28S%5Ccap%20A%29%5Ccap%28S%5Ccap%20B%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B350%2B100-50%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B450-50%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B400~elements.%7D%5C%5C%5C%5C%5C%5C%20%5Ctextsf%7BThere%20are%20400%20integers%20in%20S%20that%20are%20divisible%20by%202%20or%207.%7D%20%5Cend%7Barray%7D) If you're having problems understanding the answer, try to see it through your browser: brainly.com/question/2105863
If you're having problems understanding the answer, try to see it through your browser: brainly.com/question/2105863
Tags: <em>set theory divibilility divisible integers union intersection</em>
 
        
             
        
        
        
5 equals 5/1.  Simple as that.
 
        
             
        
        
        
Answer:
Step-by-step explanation:
<u>Given equations:</u>
<u>Add together:</u>
- -8x + 8y + 3x - 8y = 8 - 18
- - 5x = - 10
Correct option is D
 
        
             
        
        
        
2nd month: (2000 - 35) 1.01 = 1984.65
3rd month: (1984.65 - 35) 1.01 = 1969.15
        
                    
             
        
        
        
Answer:
The 99% confidence interval = (126.93,157.67)
Step-by-step explanation:
The formula for Confidence Interval =
Mean ± z × Standard deviation /√n
Mean = 142. 3 mmHg 
Standard deviation = 20.8 mmHg. 
n = 12
Z score for 99% confidence interval = 2.56
Confidence Interval =
142.3 ± 2.56 × 20.8/√12
142.3 ± 2.56 × 6.0044427996
142.3 ± 15.371373567
Confidence Interval
= 142.3 - 15.371373567
= 126.92862643
≈ 126.93
142.3 + 15.371373567
= 157.67137357
≈ 157.67
Therefore, the 99% confidence interval = (126.93,157.67)