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lakkis [162]
3 years ago
11

Please help! Brainliest to correct!

Mathematics
1 answer:
jekas [21]3 years ago
8 0

Answer:

1.83 hours

Step-by-step explanation:

Time is inversely proportional to speed

Implies that T = k/R, where k is the constant of proportionality

Thus, the product T × R is a constant for any given valued of R,T.

Hence, 3 × 14 = t × 23

t = (3×14) ÷ 23

t = 1.83 hours

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One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
3 years ago
Read 2 more answers
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
The sum of a number and twenty-six, divided by twelve is equal to seven! <br><br> Please!!
Travka [436]

Answer:

58

Step-by-step explanation:

1. let x be the unknown number

2. make an expression

x + 26/12 = 7/1

3. cross multiply

x +26 × 1 = x + 26

12 × 7  = 84

 x + 26 = 84

4. move variables on one side and numbers on other side of the equal sign

x + 26 = 84

   - 26    -26

x = 58

4 0
2 years ago
How do you explain 15 video games to 18 video games in ratios and rates?
tiny-mole [99]

15 vg

18 vg

Just put a line in-between them to make a fraction.

3 0
3 years ago
I need help factoring this polynomial please.
Mashcka [7]

You get (2x+3)(4x^2-6x+9) when you factor 8x^3+27=0. You just divide by 3 to simplify it.


3 0
3 years ago
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