The external angle of a polygon can be found with the following formula:

n is the amount of sides to the polygon.
There are 9 sides to this polygon. Plug this value into the equation:

The exterior angle of a polygon is 140.
There is an equilateral triangle that affects segment JKL. The exterior angle and the angle of two of the sides of the equilateral triangle are added in this case.
An equilateral triangle always has angles of 60-60-60. Therefore, you can find the angle of JKL with the following equation:

The maximum angle of a line is 180. The angles combined together are 200, so you will have to subtract the difference of 200 and 180 from the combined angles.
The angle of line JKL is
160 degrees.
There would be 102 zeros in 100 googol
Answer:
≈419.4 cm.
Step-by-step explanation:
To solve this problem, you will need to set up an exponential graph as shown:
y= 40 ·
The 40 represents the initial height of the tree, while (1.6) represents the annual growth rate. 'x' represents the amount of years elapsed.
We can simply solve this by substituting 5 for x:
y= 40· 
y ≈ 419.4 cm.
Answer:
A. 133 degrees
Step-by-step explanation:
You add the two known interior numbers in the triangle to find the unknown exterior variable. In this case, the two known interior numbers are 83 and 50. 83 + 50 = 133
Intersection of E and A: E n A = { 8 }
Union of E and A : E U A = { -2, 3, 0, 6 , 8 }
<em><u>Solution:</u></em>
<em><u>The sets E and A are given below:</u></em>
E = { -2, 3, 8 }
A = { 0, 6 , 8 }
<em><u>Find the intersection of E and A</u></em>
Intersection of E and A means that, set containing all elements of E that also belong to A
Therefore,
From sets E and A,
E n A = { 8 }
<em><u>Find the union of E and A</u></em>
union of E and A contains all elements of set E and set A
E U A = { -2, 3, 0, 6 , 8 }