Answer:
The workers will need 10 days to finish the job.
Step-by-step explanation:
To solve this question we can use a compound rule of three. We have:
10 road workers -> 5 days -> 2h/day
2 road workers -> x days -> 5h/days
The first thing we should do is analyze how the proportions between the variables work, if they're inversely or directly proportional. If we raise the number of workers we expect that the amount of days needed to finish the job lowers and if we raise the number of hours worked in a day we expect that the workers would need less days to finish the job. So we need to invert the fractions that are inversely proportional to the amount of days worked, then we have:
2 -> 5 -> 5
10-> x -> 2
x = (5*2*10)/(2*5) = 100/10 = 10 days
Answer:
Area =
square units
Step-by-step explanation:
<u>Key skills needed: Area of a parallelogram</u>
1) This shape is a parallelogram, and the way to find the area of a parallelogram is:

A = area
b = base (the side at the bottom
h = the height ( the length that runs from one side to another and makes a right angle)
2) The base (b) would be 3x. The height (h) would also be 3x
3) This means A =
3 times 3 is 9 --> and x times x is 
Therefore the area is --> 
<em>Hope you understood and have a nice day!! :D</em>
Answer:
Part A = $180
Part B = $104
Step-by-step explanation:
Part A:
You do 255÷5=51
51 x 4 = 180
Part B:
You do 130÷5=26
26 x 4 = 104
Answer:
8x + 12
Step-by-step explanation:
3(x + 4) + 5x
3x + 12 + 5x
8x + 12
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)