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disa [49]
3 years ago
5

Lupita rides a taxi that charges a flat rate of $6.75 plus $3.20 per mile. If the taxi charges Lupita $40.03 in total for her tr

ip, how many miles is her ride?
Mathematics
2 answers:
tester [92]3 years ago
8 0
The answer is found by subtracting 6.75 from the final price which gives you 33.28 , then dividing that by 3.20 which gives you an answer of 10.4
MrRa [10]3 years ago
7 0
First set set up an equation :
6.75+3.20x=40.03
Subtract:
6.75-6.75+3.20x=40.03-6.75
Divide
3.20x/3.20=33.283.20
x=10.4
The number of miles is 10.4
Hope it helped!!
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What is 2-1+5×4×11 order of operation ​
Alenkasestr [34]

Answer:

221

Step-by-step explanation:

2 - 1 + 5 · 4 · 11 = 2 - 1 + 20 · 11  = 2 - 1 + 220

2 - 1 + 220 = 1 + 220

7 0
3 years ago
A basketball team played six games. In those games, the team won by 8 points, lost by 25,won by 9, won by 10,lost by 1, and won
Aneli [31]

Answer:

about 10 without a remainder of 4

Step-by-step explanation:

So, add up the number and divide by how many number you have (definition of mean). 8 + 25 + 9 + 10 + 11 + 1 all divide by 6 (since there are 6 numbers)

8 + 25 + 9 + 10 + 11 + 1 is 64.

64/6 is about 10 without a remainder of 4

4 0
3 years ago
Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:
Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2

(4+1)^2=(4-1)^2+(4)^2

(5)^2=(3)^2+(4)^2

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2

(9+1)^2=(9-1)^2+(6)^2

(10)^2=(8)^2+(6)^2

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2

(9+4)^2=(9-4)^2+(12)^2

(13)^2=(5)^2+(12)^2

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2

(16+1)^2=(16-1)^2+(8)^2

(17)^2=(15)^2+(8)^2

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2

(16+4)^2=(16-4)^2+(16)^2

(20)^2=(12)^2+(16)^2

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2

(16+9)^2=(16-9)^2+(24)^2

(25)^2=(7)^2+(24)^2

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2

(25+1)^2=(25-1)^2+(10)^2

(26)^2=(24)^2+(10)^2

So (10,24,26) is another.

Let (x,y)=(5,2).

(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2

(25+4)^2=(25-4)^2+(20)^2

(29)^2=(21)^2+(20)^2

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2

(25+9)^2=(25-9)^2+(30)^2

(34)^2=(16)^2+(30)^2

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2

(25+16)^2=(25-16)^2+(40)^2

(41)^2=(9)^2+(40)^2

Another is (9,40,41).

5 0
3 years ago
How do you solve please help geometry
maxonik [38]
Your diagram doesn't clearly define what values correspond to what, can you explain.
7 0
3 years ago
WILL GIVE BRAINLIEST
miss Akunina [59]

Answer:

the answer is no.a parallelogram is not a rectangular but the opposite is true. the reason is a cause of parallelogram's diagonals.they might not be equal in parallelogram but in rectangular they must be equal.

Step-by-step explanation:

3 0
3 years ago
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