Is 0.62473 a member of the set? For each set of real numbers

9.a )Explain why plane JKL is not an appropriate

VLD [36.1K]

Answer:

I will attach the missing drawing with the answer.

9.b)

Plane JKM

Plane JLM

Plane KLM

Step-by-step explanation:

The drawing for this question is missing. I will attach it with the answer.

9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.

Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.

9.b) We can name the plane using three points that don't lie in the same line.

Three possible names for the plane are :

Plane JKM

Plane JLM

Plane KLM

6 0

2 years ago

If you help me I'll make as brilliant

MissTica

The answer is A) 3/100.

5 0

2 years ago

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What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

4 0

2 years ago

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Why does 3^4 x 3^6 simplify to 3^10 instead of 9^10

k0ka [10]

Answer:

3^10

Step-by-step explanation:

Because the rules of index

3^4 = 3*3*3*3

3^6 = 3*3*3*3*3*3

(3^4)(3^6)=

3*3*3*3*3*3*3*3*3*3 = 3^10

4 0

2 years ago

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¿cuanto pesa cada uno de nuestros 3 personajes?

sergij07 [2.7K]

Resolviendo el sistema de ecuaciones veremos que:

niña = 23kg
niño = 28kg
perro = 18kg.

<h3>¿Como resolver el sistema de ecuaciones?</h3>

Aqui tenemos el sistema de ecuaciones:

Niña + niño = 51kg

Niño + perro = 46 kg

Niña + perro = 41kg

Para resolver esto, lo primero que debemos hacer es aislar una variable en una de las ecuaciones, por ejemplo, podriamos aislar "perro" en la tercera:

perro = 41kg - niña

Ahora reemplazamos eso en la segunda para obtener:

niño + (41kg - niña) = 46kg

niño - niña = 46kg - 41kg = 5kg

niño = niña + 5kg

Ahora logramos obtener la variable "niño" en terminos de la variable "niña". Podemos reemplazar esto en la primera ecuacion del sistema.

niña + niño = 51kg

niña + (niña + 5kg) = 51kg

2*niña = 51kg - 5kg = 46kg

niña = 46kg/2 = 23kg.

Ahora que sabemos esto, usamos las otras ecuaciones para encontrar el peso del niño y el perro:

niño = niña + 5kg = 23kg + 5kg = 28kg

perro = 41kg - niña = 41kg - 23kg = 18kg.

Sí quieres aprender más sobre sistemas de ecuaciones, puedes leer:

brainly.com/question/17174746

6 0

2 years ago