Answer:
I believe the answer is C :)
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
I dont know for sure though...
Answer:
r^2 * 1/s^4 * t^5
Step-by-step explanation:
r^2 * 1/s^4 * t^5
s^-4 = 1/s^4
Answer:
13750
Step-by-step explanation:
Let 'x' be the number of bulbs produced in second shift
Number of bulbs produced in 1st shift= 5.5x
Total number of bulbs= 5.5x+x
16250=5.5x+x
x=2500
Number of bulbs produced in shift 1= 5.5×2500
= 13750
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
