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Diano4ka-milaya [45]
3 years ago
7

What's the ordered pair for point H in the graph above?

Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

C) (5,0)

Step-by-step explanation:

1. The correct answer is C) because when we move five units to right from the origin, and zero units up, we end up at point H!

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Write a ratio this is equivalent to 9/27
tresset_1 [31]
9/27

there are infinite ratios equal to 9/27


one if the ratio is 1/3
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Plz help!!!!! <br> ctc math
bija089 [108]

Answer:

7,13,37,55,103

Step-by-step explanation:

y = 5 + 2x^2

if x =1

y = 5 + 2(1)^2

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y=5 + 2 or y = 7

you substatute each one in for x to solve for y

5 0
3 years ago
Point m is the midpoint of kL. M(1,-1) and L(8,-7. What are the coordinates of point k?
Phoenix [80]

Answer: (-6, 5)

<u>Step-by-step explanation:</u>

Use the Midpoint Formula: \dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)

Separate the x's and y's and solve them individually:

\dfrac{x_k+x_L}{2}=x_m\qquad \qquad \qquad \qquad\dfrac{y_k+y_L}{2}=y_m\\\\\\\dfrac{x_k+8}{2}=1\qquad \qquad \qquad \qquad \qquad \dfrac{y_k-7}{2}=-1\\\\\\x_k+8=2\qquad \qquad \qquad \qquad \qquad y_k-7=-2\\\\\\x_k\quad =-6 \qquad \qquad \qquad \qquad \qquad y_k\qquad =5

            So, the k-coordinate is (-6, 5)

3 0
3 years ago
Sadie simplified the expression √54a^7b^3, where a&gt;=0, as shown: √54a^7b^3= √3^2•6•a^2•a^5•b^2•b=3ab √6a^5b
Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote a^7 as a^2 * a^5 instead of a^6 * a.

The square root of a^6 is a^3 and so she could have further simplified.

The correct simplification is shown below:

\sqrt{54a^7b^3} = \sqrt{2 * 3 * 3 * 3 * a^6 * a * b^2 * b} \\  \\= \sqrt{3^2 * a^6 * b^2 * 6 * a * b} \\\\= 3a^3b\sqrt{6ab}

4 0
3 years ago
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