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3 years ago

HELP ME PLEASE PLEASE PLEASE PLEASE PLEASE WITH THESES TO NOBODY WILL HELP PLEASEEEEE

Mathematics

1 answer:

aksik [14]3 years ago

6 0

Answer:

number 3 is 1 anything to the power of 0 is 1

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Me.Webster is buying carpet for n exercise room in his basement. The room will have an area of 230 square ft. The width of the r

Kipish [7]

Area is length times width. Because dividing is the exact opposite of multiplying, we can divide for the answer.

230 divided by 12.5 equals 18.4

230 ÷ 12.5 = 18.4

4 0

3 years ago

A lock consist of 4 dials where each dial has 6 letters what is the probability of guessing the right combination in one try’s

VARVARA [1.3K]

Using it's concept, it is found that the probability of guessing the right combination in one try’s is of $\frac{1}{1296}$ .

<h3>What is a probability?</h3>

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there are 4 dials, each with a $\frac{1}{6}$ probability of getting it correct, hence the probability of getting the right combination is given by:

$p = \left(\frac{1}{6}\right)^4 = \frac{1}{1296}$ .

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

5 0

2 years ago

Explain how you would graph the following set of parametric equations by plotting points and describing the orientation.

lyudmila [28]

Concept:

First eliminate the t from x=3t and then put it in y=t² and then graph it. As, limit of t is not restricted so t ∈ R(all real numbers)

As it is difficult to make graph here so I have solved it by hand and add all detail regarding it.

6 0

3 years ago

Read 2 more answers

Find the area of the region between the curve y= 2ln(x) and the horizontal axis for 1<= x <= 4

marissa [1.9K]

Answer:

5.09 units

Step-by-step explanation:

Given equation

$y=2\ln x=f(x)$ in the interval $1\le x\le 4$

So we integrate $y$ in the given interaval

$\int f(x)=2\int\limits^4_1 {\ln x}dx$

Let us integrate $\ln x$ first.

let

$u=\ln x, dv=dx$

$du=\dfrac{1}{x}, v=x$

$\int\ln x dx=udv$

Using integration by parts we get

$uv-\int vdu$

$=x\ln x-\int x\dfrac{1}{x}dx$

$=x\ln x-dx$

$=x\ln x-x+C$

So here

$\int f(x)=2\int\limits^4_1 {\ln x}dx\\ =2(x\ln x-x)_1^4\\ =2[(4\ln 4-4)-(1\ln 1-1)]\\ =2[4\ln 4-4+1]\\ =5.09\ units$

The area of the the region between the curve and horizontal axis is 5.09 units.

5 0

3 years ago

Number 6 please thanks :)

tatuchka [14]

Answer:

60° = m∠CED

30° = m∠AEB

Step-by-step explanation:

Since 90° is the m∠CEB, we already know the angle measures of the other two that got to be half and half of each other:

m∠AEB = ½m∠CED

$30 = \frac{1}{2}(60)$

This is like the 30°-60°-90° theorem. Always keep these in mind because you will never know when they will come in handy. The other one is called the 45°-45°-90° theorem, which in this case would not apply because two legs would have to congruent, which in this case they are not.

I am joyous to assist you anytime.

7 0

4 years ago