Answer:
x = 6 x = -7
Step-by-step explanation:
Subtract 12 from each side:
x^2 + x - 30 - 12 = 12 - 12
Simplify:
x^2 + x - 42 = 0
Solve with quadratic formula using both +/- after the first -1:
x =
Simplify:
x = 6
x = -7
WRITE USING ALGEBRA
1 answer:
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Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
Answer:
a) Number of calories burned in hours of cycling
and Number of calories burned in
hours of Swimming is
.
b)The equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds is .
Step-by-step explanation:
Given:
5 pounds of body fat = 16000 calories
Number of calories burn in 1 hour of cycling = 600
Number of calories burn in 1 hour of swimming = 400
Part a:
We need to find number of calories will Carol burn in hours of cycling and number of calories will Carol burn in
hours of swimming.
Solution:
Now we know that;
1 hr of cycling = 600 calories burned
hr of cycling = Number of calories burned in
hours of cycling.
By using Unitary method we get;
Number of calories burned in hours of cycling =
Also we know that;
1 hr of swimming= 400 calories burned
hr of swimming = Number of calories burned in
hours of swimming.
By using Unitary method we get;
Number of calories burned in hours of Swimming =
Hence Number of calories burned in hours of cycling
and Number of calories burned in
hours of Swimming is
Part b:
We need to write equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds.
Solution:
Now given;
5 pounds = 16000 calories.
So we can say that;
Total number of calories to be burn is equal to sum of Number of calories burned in hours of cycling and Number of calories burned in
hours of Swimming.
framing in equation form we get;
Now dividing both side by 100 we get;
Hence the equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds is .