Answer:
Bl^2+4Bl*Fh
Step-by-step explanation:
I'm not quite certain what "draw a net" means here. But for part b, we are doing the formula. The bottom part is a square(assumingly so take this with a grain of salt), thus making the base equal to 3*3 cm or 9 cm^2. The triangular faces are each 3*2.24 cm or 6.72 cm^2. We then multiply this by 4 to get 26.88. Thus, the equation is Bl^2(Base length squared)+Bl*Fh(Face height, I forgot the official name sorry about that)*4 for part b.
Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters] = 2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8
The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598
Note: The third term of the sequence should be 
instead of 
, otherwise the sequence has no common ratio.
Given:
The given sequence is
To find:
The common ratio of the given sequence.
Solution:
The quotient of each pair of consecutive terms are:
Similarly,
And,
Therefore, the common ratio of the given sequence is 
or 0.75.
Answer: y = − 
Step-by-step explanation:
