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3 years ago

It is -15° ourside and it increases 2° per hour what is the temperature adter 8 hours

Mathematics

2 answers:

neonofarm [45]3 years ago

7 0

1°, because -15° + (2° × 8 hours) = 1°

nlexa [21]3 years ago

5 0

8x2=16 -15+16= 1 so 1 wold be your answer

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If the domain of f(n) = -4n - 3 is (-1, 1/4,4}, what is the range?

ahrayia [7]

Answer:

$Range= \{1,-4,-19\}$

Step-by-step explanation:

Given

$f(n) = -4n - 3$

$n = \{-1,1/4,4\}$ --- domain

Required

Determine the range

To do this, we simply substitute the values of n in the given expression

So, we have:

$n = -1$

$f(-1) = -4 * -1 - 3 =4 - 3 = 1$

$n = 1/4$

$f(-1) = -4 * 1/4 - 3 =-1 - 3 = -4$

$n=4$

$f(-1) = -4 * 4 - 3 =-16 - 3 = -19$

Hence, the range is:

$Range= \{1,-4,-19\}$

5 0

2 years ago

1. Is it proportional?

astra-53 [7]

Answer:

Y=5(x) Yes it is porportional.

Step-by-step explanation:

So lets look at the graph.

We first have 1x = 5y

Well, that makes it seem like for each x there are 5 y.

Lets see the other values:

2x = 10y

Divide both sides by 2 tog et x alone:

1x=5y

Again, for each x, there are 5y.

This is true for each one:

3x=15y

1x=5y

4x=20y

1x=5y

5x=25y

1x=5y

and finally:

6x=30y

1x=5y.

So yes, this is poroportional.

It can be shown as x=5y, since for a single x, there are 5 y's.

Hope this helps!

5 0

3 years ago

Please help with this:)

AleksAgata [21]

Answer:

$2 \times 4 \times 3.142 = 25.136 = 25.1$

8 0

2 years ago

Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is

maw [93]

There are 120 ways in which 5 riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways $^nN_r = \frac{n!}{(n-r)!}$ ,

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways $^nN_r = \frac{n!}{(n-r)!}$ ,

Now,

Substituting values,

We get,

$^5N_5 = \frac{5!}{(5-5)!}$

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5 riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0

2 years ago

Rose writes down all of her math quiz scores. Her math scores are 98,78,84, and 96. What is the mean of her math quiz scores?

KATRIN_1 [288]

Answer:

Step-by-step explanation:

Hi, there to find the mean

you need add the numbers and count how many numbers are there and divide

In this case 98+78+84+96= 356

Now we will count

there are 4 numbers

$\frac{356}{4}$ = 89

Your mean will be 89

If you ever have trouble with mean remember this

Mean $\frac{SumofDataPoints}{NumberofDataPoints }$

well it is supposed to be:

Sum of Data Points/Number of Data Points

4 0

3 years ago