30 as a mixed number:
4√24 - 3√54 + 5√6 - √150
2 answers:
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Answer: Although A and AT have the same eigenvalues, they may actually have different eigenvectors for that particular eigenvalue. Therefore A and AT have at least one eigenvector that aren't in common.
Step-by-step explanation:
These two attachment explains the provings and counterexamples briefly and simply
