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myrzilka [38]
3 years ago
13

Can somebody help me with this question

Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0

Answer:

150

Step-by-step explanation:

Time in Distance 1+ time in distance 2= 22

let the 1st Distance be x

2nd Distance = 500-x

time = distance / speed

x/10 + (500-x)/50= 22

LCM = 50

multiply equation by 50

5x+500-x=11004

x=600

x=150 m

150 m at 10m/s

350 m at 50m/s

(hope this helps have a great day ☺️)

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Simplify the following expressions by factoring using the greatest common factor:
Sindrei [870]

Answ

Step-by-step explanation:

−42−5i 2y−1(y−2)(y−2)

8 0
3 years ago
If the area of a square is 1 square meter, how many centimeters long is each side?
aev [14]

Answer:

100 centimeters

Step-by-step explanation:

Area of a square is side x side= s x s or s²

If s² = 1 square meter

s = √1 = 1 meter

Each side is 1 meter.  To convert to centimeters multiply by 100 since there are 100 centimeters in 1 meter.

Each side is 100 centimeters

7 0
4 years ago
Angela has a collection of nickels and quarters worth $8.80. If she has 68 total nickels and quarters, how many quarters does sh
pav-90 [236]
27 quarters because 27 multiplied by $0.25 for the amount each quarter is worth is $6.75 meaning that the rest 41 coins would be Nickels multiplied by $0.05 the amount a nickel is worth giving us $8.80 dollars.

I probably said that in a confusing way sorry but the answer is (27 quarters)
4 0
3 years ago
Identify the GCF of 6x^2y^2 − 8xy^2 + 10xy
myrzilka [38]

Answer:

The GCF for the numerical part is 2

Step-by-step explanation:

6x^2y^2-8xy^2+10xy

It contains both numbers and variables, there are two steps to find the GCF(HCF).

1). Find the GCF for the numerical part 6, -8,10

2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3

3).Multiply the values together.

Find the common factors for the numerical part:

6,-8,10

Factors of 6

6: 1,2,3,6

Factors of -8

-8: -8,-4,-2,-1,1,2,4,8

Factors of 10

10:1,2,5,10

Common factors of 6,-8, 10 are 1,2

The GCF Numerical=2

The GCF Variable= xy^2

Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2

6 0
2 years ago
a student ran out of time on a multiple choice exam and randomly guess the answers for two problems each problem have four answe
katen-ka-za [31]

Answer:

The probability that he answered neither of the problems correctly ​is 0.0625.

Step-by-step explanation:

We are given that a student ran out of time on a multiple-choice exam and randomly guess the answers for two problems each problem have four answer choices ABCD and only one correct answer.

Let X = <u><em>Number of problems correctly ​answered by a student</em></u>.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r}\times p^{r}\times (1-p)^{n-r};x=0,1,2,3,....    

where, n = number of trials (samples) taken = 2 problems

           r = number of success = neither of the problems are correct

           p = probability of success which in our question is probability that

                 a student answer correctly, i.e; p = \frac{1}{4} = 0.75.

So, X ~ Binom(n = 2, p = 0.75)

Now, the probability that he answered neither of the problems correctly ​is given by = P(X = 0)

             P(X = 0) = \binom{2}{0}\times 0.75^{0}\times (1-0.75)^{2-0}

                            = 1 \times 1\times 0.25^{2}

                            = <u>0.0625</u>

6 0
4 years ago
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