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Llana [10]
2 years ago
13

Identify the GCF of 6x^2y^2 − 8xy^2 + 10xy

Mathematics
1 answer:
myrzilka [38]2 years ago
6 0

Answer:

The GCF for the numerical part is 2

Step-by-step explanation:

6x^2y^2-8xy^2+10xy

It contains both numbers and variables, there are two steps to find the GCF(HCF).

1). Find the GCF for the numerical part 6, -8,10

2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3

3).Multiply the values together.

Find the common factors for the numerical part:

6,-8,10

Factors of 6

6: 1,2,3,6

Factors of -8

-8: -8,-4,-2,-1,1,2,4,8

Factors of 10

10:1,2,5,10

Common factors of 6,-8, 10 are 1,2

The GCF Numerical=2

The GCF Variable= xy^2

Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2

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Answer:

Step-by-step explanation:

The formula for this is

∠G = 1/2(arcEH - arcHF)

We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF

Filling in the formula with what we have:

5x-10=\frac{1}{2}(195-(8x+17))

which simplifies down a bit to

5x-10=\frac{1}{2}(195-8x-17) which simplifies down a bit more to

5x-10=\frac{1}{2}(178-8x) Multiply both sides by 2 to get rid of the fraction and get:

2(5x - 10) = 178 - 8x which of course simplifies to

10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:

18x = 198 so

x = 11. Now we can find the measure of arcHF:

arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.

arcEH + arcHF = arcEHF so

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Answer: Determine if the following side lengths could form a triangle.

Prove your answer with an inequality.

8,17,24

Step-by-step explanation:

Determine if the following side lengths could form a triangle.

Prove your answer with an inequality.

8,17,24

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