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daser333 [38]
3 years ago
14

Writing linear functions given a graph, I have to know the equation, slope, and y intercept anything helps!!

Mathematics
2 answers:
djyliett [7]3 years ago
7 0
Given the points on the graph, (-3,0) and (0,5), we can solve for the slope using the formula:

m = (y2 - y1)/(x2 - x1) = (5-(-3)) / (0- (-3)) = 5/3

So the slope is 5/3 (you can verify on the graph, using the rise/run concept).

The y-intercept is the value of y when x = 0. If you look at the two coordinates that I used for solving the slope, the coordinate ( 0, 5) will give you the y-intercept of 5, since its ordered pair of x value = 0.

So, y-intercept = 5.

We now have the necessary variables needed for your linear equation:

y = 5/3x + 5.

It has a positive slope, thus the line sloping upward.

Hope this helps you :)
docker41 [41]3 years ago
4 0
…I’m so sorry I can’t help but you got this
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Every positive real number has a positive and a negative square root, the ________ root is called the principal root. *
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  B) positive

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Write the augmented matrix for the following system of equations.<br> y + 2x = 0<br> -3x + 2y = -2
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3 years ago
Can someone plz help with this question idk how to do it im stooopid
V125BC [204]

Answer: 96 square units (choice B)

==============================================

Explanation:

Triangle OBI has a base of OI = 12 units along the horizontal component, and CB = 8 is the vertical component or the height.

area of triangle OBI = 0.5*base*height

area of triangle OBI = 0.5*12*8

area of triangle OBI = 48 square units

--------------------------------------

Now find the area of the trapezoid GNIO. The two horizontal components are the parallel bases GN = 4 and OI = 12. The height of this trapezoid is the vertical component CD = 6, where point D is added on to be at location (0,-6) on the graph.

area of trapezoid = (height*(base1+base2))/2

area of trapezoid GNIO = 6*(4+12)/2

area of trapezoid GNIO = 48

Coincidentally, the triangle and trapezoid both have the same area

--------------------------------------

The last thing to do is add the two areas of the triangle and trapezoid

total area = (area of triangle OBI) + (area of trapezoid GNIO)

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