The containers must be spheres of radius = 6.2cm
<h3>
How to minimize the surface area for the containers?</h3>
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:

Then we must solve:
![V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2AR%5E3%20%3D%201000cm%5E3%5C%5C%5C%5CR%20%3D%5Csqrt%5B3%5D%7B%20%20%281000cm%5E3%2A%5Cfrac%7B3%7D%7B4%2A3.14%7D%20%29%7D%20%3D%206.2cm)
The containers must be spheres of radius = 6.2cm
If you want to learn more about volume:
brainly.com/question/1972490
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Answer:
He has 672 nails
Step-by-step explanation:
168/.25
$8 + $7 + $13 + 15 = $43
$x - $43 = $12
x = $55
i am a mathematics teacher. if anything to ask please pm me
10 I think..I might be wrong
Answer:
Sequoia sold 2 chap sticks while Raven sold 4.
Step-by-step explanation:
Since two friends, Sequoia and Raven, sold organic chap sticks at the local market, and Sequoia sold her chap sticks for $ 4 and Raven sold hers for $ 3 each, and in the first hour, their total combined sales were $ 20, if in the first hour, the friends sold a total of 6 chap sticks between them, to determine the number of chap sticks each of the friends sold during this time the following calculation must be performed:
6 x 4 + 0 x 3 = 24
5 x 4 + 1 x 3 = 23
2 x 4 + 4 x 3 = 20
Therefore, Sequoia sold 2 chap sticks while Raven sold 4.