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3 years ago

Where is each located in a multiplication problem

Mathematics

1 answer:

Verdich [7]3 years ago

7 0

???/where is what located

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Suppose that scores on a test are normally distributed with a mean of 80 and a standard deviation of 8. Answer the questions bel

Studentka2010 [4]

Answer:

(a) 84.2

(b) 10.6

Step-by-step explanation:

To solve this questions we can use the standardization formula, where we know that if $X\sim N(\mu,\sigma^2)$ then $Z=\frac{X-\mu}{\sigma} \sim N(0,1)$

So for

(a) we know that the z score for the 70th percentile is 0.524, so using the normalization equation we have

$\frac{X-\mu}{\sigma}=0.524$

$X=0.524*8+80=84.192$

(b) We can procede as above and get

$P(X$

3 0

4 years ago

Read 2 more answers

I need the answer quickly. 6(3-2)/6

wel

Answer:

I think the answer would be 1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLS HELP I WILL MARK BRAINLIST

storchak [24]

It’s d

Because…
A= 77% which is equivalent to .77, which is less than 1

B= 10/8 because it is a little more than one

And by looking at the line you can see how C and D are marked correctly because both of them are over 2, and D is a little bigger than C

7 0

3 years ago

A movie was shown 6 times every day from November 24 through December 19. How many times was the movie shown in all? (Note: The

katen-ka-za [31]

Answer:

Answer: A. 138 times

How?

During that time period there were 23 days so 23 multiplied by the amount of times played per day (6)

You get the answer 138

Step-by-step explanation:

4 0

3 years ago

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Find the distance and displacement for the following figures :

Vinil7 [7]

The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters

<h3>How to find the distance and displacement in each trajectory</h3>

The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the <em>initial</em> and <em>final</em> point of a trajectory. Then, we have the following results for each case:

Case I

Distance

d = 5 m + 0.5π · (7 m)

d ≈ 15.996 m

Displacement

$D = \sqrt{(12\,m)^{2}+(7 m)^{2}}$

D ≈ 13.892 m

Case II

Distance

d = 8 · (60 cm)

d = 480 cm

Displacement

$D =\sqrt{(240\,cm)^{2}+(240\,cm)^{2}}$

D ≈ 339.411 cm

To learn more on displacement: brainly.com/question/11934397

#SPJ1

4 0

2 years ago