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2 years ago

Which of the following equations represents a line that passes through the points

Mathematics

2 answers:

Ksivusya [100]2 years ago

5 0

Step-by-step explanation:

the slope = (0+15)/(-1-4)=15/(-5)= -3

the Equation :

y+15= -3(x-4)

y+15 = -3x+12

y +3x=12-15

3x + y = -3

so, the correct answer is II only

lara [203]2 years ago

4 0

Answer:

y + 15 = -3(x - 4) II only

Step-by-step explanation:

y2 - y1 / x2 - x1

0 - (-15) / -1 - 4

15 / -5

= -3

- Since the slope is -3, the answer can't be 1.

y + 15 = -3(x - 4)

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3 years ago

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2 years ago

Read 2 more answers

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

Kaiya says the complex fraction /= is equivalent to the complex fraction =/. Is she correct? Explain your answer.

Arturiano [62]

Answer:

Well i think so

Step-by-step explanation:

its just an equal sign on different sides

6 0

2 years ago