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Answer:
(a) Along the xy-plane,
7x + 6y = 0
(b) Along the yz-plan,
2y - 3z = 0
(c) Along the xz-plane,
7x - 3z = 0
Step-by-step explanation:
To describe the given set.
Given the plane (7, 6, -3),
We have the equation as
7x + 6y - 3z = 0
(a) Along the xy-plane, z = 0, and we have
7x + 6y = 0
(b) Along the yz-plan, x = 0, and we have
6y - 3z = 0
Or
2y - 3z = 0
(c) Along the xz-plane, y = 0, and we have
7x - 3z = 0
Answer:
Slope of PQ = 0
Slope of MN = infinity
PQ and MN are perpendicular to each other
Step-by-step explanation:
for any two points (x1, y1), (x2, y2)given in coordinate plane slope is given by

For any line if slope is zero it is parallel to X axis and perpendicular to Y axis
For any line if slope is infinity it is parallel to Y axis and perpendicular to X axis
Also we know X and Y are perpendicular to each other.
Since slope of PQ is zero it is parallel to X axis and perpendicular to Y axis
Since slope of MN is infinity it is parallel to Y axis and perpendicular to X axis.
Thus two lines PQ and MN are perpendicular to each other.