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Phoenix [80]
3 years ago
6

Math Problem:

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

Her answer is not reasonable. Her average is 83.

Step-by-step explanation:

Add all of her test grades together (96+82+78+76=332)

To find the average, you need to add all test grades she got and then divide the sum by the total number of numbers added (in this case, we added 4 tests together, so we need to divide by 4)

\frac{332}{4} =83

So she added wrong and forgot to divide by the total number of tests.

You might be interested in
Find the variable x.
grandymaker [24]

Answer:

x = 7

Step-by-step explanation:

The inscribed angle (5x - 3) is equal to half the measure of the intercepted arc

5x - 3 = 0.5(9x + 1) ← multiply both sides by 2

10x - 6 = 9x + 1 ( subtract 9x from both sides )

x - 6 = 1 ( add 6 to both sides )

x = 7

5 0
3 years ago
6/3 + (-1/6) = ?<br><br> (These are supposed to be fractions)
Phoenix [80]

Answer: 11/6 or 1 5/6

<u>Simplify 6/3</u>

6/3÷3/3=2/1

<u>Change 2/1</u>

2/1×6/6=12/6

New Problem: 12/6+(-1/6)

<u>Add</u>

12+-1/6=11/6

<u>Simplify</u>

11/6 = 1 5/6

6 0
3 years ago
Which of the following is a solution for the absolute value inequality |2x – 3| &gt; 6?
Mice21 [21]
This breaks into two inequalities:

2x - 3 > 6

and

-2x + 3 > 6

------------------------

2x - 3 > 6

Add 3 to both sides:

2x > 9

Divide 2 to both sides:

x > 4.5

-----------------------

-2x + 3 > 6

Subtract 3 to both sides:

-2x > 3

Divide -2 to both sides:

x < -1.5
3 0
3 years ago
Read 2 more answers
Ques
natulia [17]

Answer:

C

Step-by-step explanation:

In a Pythagorean triple the square on the longest side is equal to the sum of the squares on the other 2 sides.

A

longest side = 10 ⇒ 10² = 100

6² + 8² = 36 + 64 = 100

A is a Pythagorean triple

B

longest side = 17 ⇒ 17² = 289

8² + 15² = 64 + 225 = 289

B is a Pythagorean triple

C

longest side = 9 ⇒ 9² = 81

5² + 8² = 25 + 64 = 89

89 ≠ 81

C is not a Pythagorean triple

D

longest side = 13 ⇒ 13² = 169

5² + 12² = 25 + 144 = 169

D is a Pythagorean triple

6 0
3 years ago
The product of two consecutive odd integers is 782. What are the integers?
Alex Ar [27]

Call the smaller of the two odds = n

Call the next number in the sequence = n + 2

n*(n +2) = 782           Remove the brackets.

n^2 + 2n = 782          Subract 782 from both sides.

n^2 + 2n - 782 = 0    We are going to have to factor this.

Discussion

This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.

For example, you could use 783, (which factors) instead of 782 .

Solve

n^2 + 2n - 783 = 0

(n + 29)(x - 27) = 0

<u>Solution One</u>

n - 27 = 0

n = 27

The two odd consecutive integers are 27 and 29.

<u>Solution Two</u>

n + 29 = 0

n = - 29

The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.

7 0
4 years ago
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