Answer:
Step-by-step explanation:
exponents raised to a - power is an inverse function probably not the right word
a^-b = 1/(a^b) example 4^-2 = 1/(4^2) = 1/16
so (7^-1)^-1 is a double inverse which is back to the original number 7
inverted 7 twice
(7^-1)^-1 = (1/7)^-1 = 1/(1/7) = 7 trust me or use your calculator
since the coeffients are the same just add the powers... some exponent rule
5^2 * 5^4 * 5^-3 = 5^(2+4-3) = 5³
here is it written out
5^2 * 5^4 * 5^-3 = 5² × 5^4 × 5^-3 = (5×5) × (5×5×5×5) × (1/5×1/5×1/5)
5×5 × 5× (5×5×5 × 1/5×1/5×1/5) (5×5×5 × 1/5×1/5×1/5) = 1
5×5×5 = 5³
so
What integers do you want the problem to be
Wwwooooooowwwww
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Step-by-step explanation:
f (10) = 3×10 - 8
= 30 - 8
= 22
f (3) = 3×3 - 8
= 9 - 8
= 1
f(10) - f (3) = 22 - 1
= 21
That depends.
-- If you're rounding to the nearest ten-thousandth, it's 4.5713 .
-- If you're rounding to the nearest thousandth, it's 4.571 .
-- If you're rounding to the nearest hundredth, it's 4.57 .
-- If you're rounding to the nearest tenth, it's 4.6 .
-- If you're rounding to the nearest whole number, it's 5 .
-- If you're rounding to the nearest ten, or to any larger place, it's zero.
